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wiki:astronomy:observational_astronomy:measurements:radiative_flux [2023/11/11 21:01] – Roy Prouty | wiki:astronomy:observational_astronomy:measurements:radiative_flux [2023/11/14 11:11] (current) – removed Roy Prouty | ||
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- | The radiative energy of a source can be given either in relative terms via some [[~: | ||
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- | Recall from the discussion on [[~: | ||
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- | ===== Radiative Energy ===== | ||
- | The energy associated with the liberation of these electrons is the radiative energy we seek to measure. This energy interacts with the semiconductor substrate and liberates photoelectrons at a rate assumed to be linear with respect to the integration-time. | ||
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- | $$E = \frac{hc}{\lambda}$$ | ||
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- | Energy carries the normal units Joules ($[E]=~ J$)((Also of relevance is the $erg$. | ||
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- | So these counts are proportional not to the total energy of a target observed by the telescope, but to the differential amount of that energy called (in the broadest sense) the spectral radiance. | ||
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- | ===== Spectral Radiance ===== | ||
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- | The differential amount of energy shown in the numerator of the right hand side tends to vanish as the factors in the denominator tend to zero. The spectral radiance (the left hand side; $I(\lambda, \theta, \phi)$) is the limiting value this ratio approaches. Is can be thought of as a " | ||
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- | $$I(\lambda, | ||
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- | The spectral radiance has units $[I(\lambda, | ||
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- | Said slightly differently, | ||
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- | Each pixel effectively integrates this spectral radiance with respect to wavelength, time, perpendicular area, and solid angle. The resulting measure of radiant energy is what is responsible for liberating photoelectrons in the CMOS semiconductor substrate which are eventually readout proportional to a voltage they generate as counts.\\ \\ | ||
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- | ===== Spectral Flux ===== | ||
- | For angularly unresolved sources, we are forced to assume that the energy we received in each pixel is the integral of all the spectral radiance that emerged from the source parallel to our line of sight. | ||
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- | $$F(\lambda) = \frac{d^4 E}{d\lambda\cdot dt\cdot d^2A_{\perp}}$$ | ||
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- | The radiative, spectral flux has units $[F(\lambda)]=J\cdot (m\cdot t\cdot m^2)^{-1}$. \\ \\ | ||
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- | {{tag> | ||