wiki:astronomy:observational_astronomy:observational_astronomy:extinction

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wiki:astronomy:observational_astronomy:observational_astronomy:extinction [2023/11/14 12:56] – Roy Proutywiki:astronomy:observational_astronomy:observational_astronomy:extinction [2023/11/14 13:11] (current) – Roy Prouty
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 From the definition of the natural logarithm: From the definition of the natural logarithm:
 $$\ln{(I_\lambda^b)} - \ln{(I_\lambda^t)} = \ln{\Biggl[\frac{I_\lambda^b}{I_\lambda^t}\Biggr]} = - \sec{z} \int_b^t \alpha_\lambda(x) dx$$ $$\ln{(I_\lambda^b)} - \ln{(I_\lambda^t)} = \ln{\Biggl[\frac{I_\lambda^b}{I_\lambda^t}\Biggr]} = - \sec{z} \int_b^t \alpha_\lambda(x) dx$$
 +
 +Employing some algebra, we are left with the ratio of two radiances.
 +
 +$$\frac{I_\lambda^b}{I_\lambda^t} = \exp{\Biggl(- \sec{z} \int_b^t \alpha_\lambda(x) dx\Biggr)}$$
 +
 +
 +From the page on the [[wiki:astronomy:magnitude|magnitude scale]], we can see that this is almost immediately relatable to the Pogson Equation. As it turns out, the only difference between the spectral, radiant fluxes reported on that page and the spectral radiances reported above is that the units are different. They're different by an integration over solid angle. Since these measurements are all derived from pixels of the same size -- and therefore observing the same solid angle -- both the flux ratio and the radiance ratio should be identical!\\ \\
 +
 +So blazing forward with this equivalence, we can re-write the Pogson Equation in terms of this atmospheric extinction relationship we've just derived.
 +
 +$$m_b-m_t = -2.5 \log_{10}\frac{I_\lambda^b}{I_\lambda^t} = -2.5 \log_{10}\Biggl[\exp{\Biggl(- \sec{z} \int_b^t \alpha_\lambda(x) dx\Biggr)}\Biggr]$$
 +
 +Let's carefully take the log-base-10 of the exponential...
 +$$m_b-m_t = -2.5 \log_{10}(e)\biggl(- \sec{z} \int_b^t \alpha_\lambda(x) dx\biggr)$$
 +
 +Finally, recalling that we want to calibrate to the top-of-the-atmosphere, we find
 +
 +$$m_t = m_b + 2.5 \log_{10}(e)\biggl(- \sec{z} \int_b^t \alpha_\lambda(x) dx\biggr)$$
 +
 +So we find that the top-of-the-atmosphere magnitude is our bottom-of-the-atmosphere = top-of-telescope magnitude with some additional magnitude that was "extincted" away from incidence as the radiance traversed the atmosphere.\\ \\
 +
 +Note that the $F$ or $I$ used in the above equations are //not// counts. They must be some unit of power. So radiance, flux, energy per second (power), or even counts-per-second.
 +
 +----
 +Sources
 +  - Lifted with minor modification from: https://slittlefair.staff.shef.ac.uk/teaching/phy241/lectures/l07/