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wiki:observational_astronomy:energy:energy_flux_counts [2023/11/10 12:09] – Roy Prouty | wiki:observational_astronomy:energy:energy_flux_counts [2023/11/10 12:28] (current) – removed Roy Prouty | ||
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- | ====== What are we measuring? ====== | ||
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- | Q: What do the values our imaging software give us mean?\\ | ||
- | A: Well, what do our pixels report to us? Answer: Counts. These are digital units derived from the on-chip analog-to-digital conversion process that is thought to be (to a first-order approximation) linear with respect to the voltage generated by liberated electrons in the pixels of the detector.\\ \\ | ||
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- | So we've passed the bill from the counts to the voltage and the associated liberated electrons. Grant me that the piling up of electrons over the integration-time generates a voltage. After that, what liberates the electrons? Answer: photons, thermal agitations, and other electromagnetic forces. For a more delicate discussion of this, refer to the [[[[wiki: | ||
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- | The thermal agitations and other electromagnetic forces arise from the detector itself. These contributions to the liberated electrons and therefore counts must be calibrated away (see [[wiki: | ||
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- | The energy associated with the liberation of these electrons is the radiative energy we seek to measure. This energy interacts with the semiconductor substrate and liberates photoelectrons at a rate assumed to be linear with respect to the integration-time. | ||
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- | $$E_{\gamma}~d\lambda = \frac{hc}{\lambda}d\lambda$$ | ||
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- | This energy carries the normal units Joules ($[E]=~ J$)((Also of relevance is the $erg$. | ||
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- | So these counts are proportional not to the total energy of a target observed by the telescope, but to the differential amount of that energy called (in the broadest sense) the spectral radiance. | ||
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- | $$I(\lambda, | ||
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- | The spectral radiance has units $[I(\lambda, | ||
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- | Said slightly differently, | ||
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- | Each pixel effectively integrates this spectral radiance with respect to wavelength, time, perpendicular area, and solid angle. The resulting measure of radiant energy is what is responsible for liberating photoelectrons in the CMOS semiconductor substrate which are eventually readout as counts.\\ \\ | ||
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- | Since each of the pixels are assumed to be sensitive to photons of the same range of wavelengths, | ||
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- | Since we do know the range of wavelengths, | ||
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- | $$F(\lambda) = \frac{d^4 E}{d\lambda\cdot dt\cdot d^2A_{\perp}}$$ | ||
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- | The radiative, spectral flux has units $[F(\lambda)]=J\cdot (m\cdot t\cdot m^2)^{-1}$. \\ \\ | ||
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